Introducing Easy Pulse: A DIY photoplethysmographic sensor for measuring heart rate

Status
Not open for further replies.
snishanth512 said:
How does the capacitor acts as an open circuit at high frequency?

I didn't get.
Click to expand...

Hi Nishanth, the capacitor acts as an open circuits because it's capacitive reactance (Something like It's resistence in AC) depends of the frequency of the signal in AC: \[X_{c} = \frac{1}{w{\cdot}C}=\frac{1}{2{\cdot}{\pi}{\cdot}f{\cdot}C}\]. As the frequency gets high in the previous equation also the admitance of the capacitor gets high.

Best regards
 

Status
Not open for further replies.

Similar threads

Menu
Log in
Register
Cookies are required to use this site. You must accept them to continue using the site. Learn more…