Introducing Easy Pulse: A DIY photoplethysmographic sensor for measuring heart rate

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Hi Nishanth !!
It's a classic (non inverting) integrator. For high frequencies the capacitor acts as an open circuit, while the resistor provides the needed feedback in DC to make it stable.

Best regards
 

How does the capacitor acts as an open circuit at high frequency?

I didn't get.
 

snishanth512 said:
How does the capacitor acts as an open circuit at high frequency?

I didn't get.
Click to expand...

Hi Nishanth, the capacitor acts as an open circuits because it's capacitive reactance (Something like It's resistence in AC) depends of the frequency of the signal in AC: \[X_{c} = \frac{1}{w{\cdot}C}=\frac{1}{2{\cdot}{\pi}{\cdot}f{\cdot}C}\]. As the frequency gets high in the previous equation also the admitance of the capacitor gets high.

Best regards
 

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