OK. How were the values of the on board resistors decided here? Considering the basic configuration in which only one FPGA pin per colour channel is assigned (pdf link to schematic
here), the voltage at FPGA pin can be up to 3.3 v. As per the user guide of the kit
here (page 53), there is a 75 ohm termination built in the cable. If the value of the on-board resistor is R, then the equation comes out to be:
R + 75 = (3.3-0.7) / I
So what value of I should I take? Also if this sounds correct (which is my main motive behind this post), is there any recommended value of I (and consequently R)? Are there any VGA standards on the current to be sourced/ taken out from the VGA port?
Similarly, how were the on board resistor values for HYSNC and VSYNC decided? Again, if it is R’, the maximum voltage at FPGA I/O pin is taken to be 3.3 v and with a 75 ohm termination built in the cable, the equation comes out to be:
R’ + 75 = (3.3 - 0.7) / I’
What would be the value of I’ which should be taken in this case? And again, if there are any VGA standards in this case recommending the current for these two pins pls?
Back calculation with the given values reveal I =7.5 mA and I’= 16.5 mA (which are far apart from each other).
In a nutshell, I wanted to understand how these values are decided and then if required, modify them in my case.
Thanks and Regards,
Arvind Gupta