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integration ..plz help..

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how do u integrate ∫ 1/(v.lnv) dv

thx
 

u=ln(v) , du=(1/v)dv

(1/ln(v))(1/v) dv =(1/u) du = ln | u | + c and, u = ln(v), so answer is ln | ln(v) | + c
 

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