Input power in dBm and conversion to Vrms

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ccw27

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dbm to vrms

Given input power in dBm, we can convert to mW by 10^(dBm/10). However we can't use 10^(dBm/20)*1E-3 to convert to Vrms, right? But if we are doing a calculation that involves a ratio of two voltages then its ok to use the above expression without taking load into account, right? The formula I want to use is LO leakage = 20log(2*Vdc/Vm) and I want to compute Vm from input power given.

Thanks
 

dbm vrms convert

Hi,
dB is always used for power ratio. To convert it any other form use the formula for the power
P = VI = I*I*R = V*V/R
and use it. It is straigh forward.

B R
M
 

Re: dBm, Vrms confusion

PdBm=10log(Pwatt/1mW)

Pwatt= vrms²/R
 

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