ccw27
Full Member level 5
dbm to vrms
Given input power in dBm, we can convert to mW by 10^(dBm/10). However we can't use 10^(dBm/20)*1E-3 to convert to Vrms, right? But if we are doing a calculation that involves a ratio of two voltages then its ok to use the above expression without taking load into account, right? The formula I want to use is LO leakage = 20log(2*Vdc/Vm) and I want to compute Vm from input power given.
Thanks
Given input power in dBm, we can convert to mW by 10^(dBm/10). However we can't use 10^(dBm/20)*1E-3 to convert to Vrms, right? But if we are doing a calculation that involves a ratio of two voltages then its ok to use the above expression without taking load into account, right? The formula I want to use is LO leakage = 20log(2*Vdc/Vm) and I want to compute Vm from input power given.
Thanks