thirtyonemessier
Newbie level 1
Hi All,
I had a 24V volt source to power on two 12V CPU Fans. I connected them in series but ended up bricking the fans.
I thought of it in terms of a voltage divider circuit, because I assumed they must be offering the same resistance:
Vo = Vs * (R2/R1+R2)
for illustration purposes, lets assume the resistance of each fan was 100ohm. Then:
12v = 24v * (100/200)
Each Fan would have got 12V but it fried the circuitry of both fans.
Can someone explain to me what stupid mistake I have done?
The fans are rated 12V 3W, i.e, 0.25A.
If I consider it to be a closed circuit, by KVL:
Vo = IxR1 + IxR2
Vo = I(R1+R2)
24v = I(100+100)
I = 0.12A
Here I < 0.25, the current drawn from the source is still less than what it should have drawn (0.25A). So why did the fans go bad?
I had a 24V volt source to power on two 12V CPU Fans. I connected them in series but ended up bricking the fans.
I thought of it in terms of a voltage divider circuit, because I assumed they must be offering the same resistance:
Vo = Vs * (R2/R1+R2)
for illustration purposes, lets assume the resistance of each fan was 100ohm. Then:
12v = 24v * (100/200)
Each Fan would have got 12V but it fried the circuitry of both fans.
Can someone explain to me what stupid mistake I have done?
The fans are rated 12V 3W, i.e, 0.25A.
If I consider it to be a closed circuit, by KVL:
Vo = IxR1 + IxR2
Vo = I(R1+R2)
24v = I(100+100)
I = 0.12A
Here I < 0.25, the current drawn from the source is still less than what it should have drawn (0.25A). So why did the fans go bad?