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Could u pls explain why when plates are thinner, losses are less? Thanks.sztibi82 said:Also if the plates are thinner, loses are less.
A.Anand Srinivasan said:actually eddy current forms circular paths and current flows through it.... so when the path is long the power loss is more (long path means more resistance)..... when the plates are made thin the path becomes very small and hence lesser power dissipation....
Would you please explain how we obtain "a series of faily high resistances in that path" after dividing the core into short segments?In ac apparatus, the cores exposed to alternating fields are laminated or subdivided into thin layers, each electrically insulated from the next, to break the eddy current path up into many short segments. See Figure 1. That in effect places a series of fairly high resistances in that path. Current flow is reduced; losses go down in proportion to the square of that current.
http://findarticles.com/p/articles/mi_qa3726/is_199612/ai_n8755644/pg_2
Do you mean "length L gets minimized" = "length L gets reduced"? If length L gets reduced, then R=ρ(L/a) should be smaller right?A.Anand Srinivasan said:the resistance is given by ρ(l/a).... here the length l gets minimized and also area a remains constant and hence the resistance increases leading to more resistance to eddy current...
If we refer to R=(ρL)/A, the normal of the A (cross-section area) should in parallel with the direction of current flow, right? The normal of the 'A' described in your last message is pependicular with the direction of current flow. So, do you think we can use the 'A' to calculate resistance against eddy current? Pls correct me if I'm wrong...A.Anand Srinivasan said:see things in the form of a circle.... by length i meant the diameter of the eddy current loop that is formed.... the area depends on the square of the length(diameter) and hence there is a length term coming in the denominator......
so when length is minimised the resistance increases.......