How to understand this assembly instruction?

[ubuntu_amateur]

inl instruction asm

there is several instructions in assembly language:

	movw	$0xcf8,%dx
	movl	$0x80003840,%eax	#
	outl	%eax,%dx
	movb	$0xfc,%dl
	inl	%dx,%eax

how to understand the last instruction? what means "inl"?
could anyone provide the material on assembly instruction set?

Thanks a lot!

 

[ubuntu_amateur]

the like as below may be helpful to understand the instruction, I have found it!
https://www-128.ibm.com/developerworks/library/l-ia.html

the suffix 'l' means 'inline', doesn't it ?

 

[echo47]

You didn't say the CPU type or assembler version, but the b/w/l opcode suffix usually means byte/word/long, which usually means 8/16/32 bit operand. So, "inl" probably means "input from 32 bit port".

 

[white_shadow]

Looks to be 8088/8086 related asm.

https://www-128.ibm.com/developerworks/linux/library/l-ia.html

 

[Pinczakko]

to ease understanding the code, I'll just comment it rightaway.

   movw   $0xcf8,%dx              ; dx = PCI address port (this is x86 architecture)
   movl   $0x80003840,%eax    ; eax = address of register 40h, function 0, device 7h, at bus 0
   outl   %eax,%dx                  ; "tell" the PCI device that we want to access register 40h in the next PCI cycle
   movb   $0xfc,%dl                 ; dx = 0xCFC = PCI data port (in x86 architecture)
   inl   %dx,%eax                    ; eax = dword starting at register 40h in the PCI device

This should be clear enough for you .

PS: The assembly language syntax is in AT&T syntax and it's an x86 (IBM-PC) architecture code. Look for AT&T syntax tutorial if you feel confused. IIRC, GAS (GNU Assembler) tutorial would be enough.