itelec
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When the output is low, the LED will be on steadily. Is that what you want, or do you want the LED off?Do you see the R with a circle on pin4?
The circle means active low.
R means reset. When you connect your comparator logic levels to this , you will get what you want with Q out = low and LED on.
No need for that. As Crutschow pointed out, just connect the LED from the output to ground instead of 6V.It sounds like you want to (or already did) configure the 555 as a pulse generator on free run, correct? Then you wish to disable it in response to a low incoming signal? You can add a 2-input AND gate to achieve this. The led lights when both inputs are high. The led is Off when either input is low. This makes the led flash.
View attachment 193449
If you want the LED off when the Reset pin is low (555 not oscillating and its output low) then you can connect the LED and series resistor from the output of the 555 to ground, not the 6V.
I am not quite sure I understand. So the and gate isn't necessary? And the output (pin 3) of the 555 timer should go to ground instead (with the LED connected). Is that all needed to make it work? And the LM393 (pin 1) should go to the reset (pin 4), right?No need for that. As Crutschow pointed out, just connect the LED from the output to ground instead of 6V.
Either use a bjt to invert the LM393 signalDo you have any idea of how to solve that?
I didn't think of the inverting input. It did the trick. Now the circuit is working perfectlyEither use a bjt to invert the LM393 signal
or the easier way:
* just interchange the (+) input with the (-) input of the LM393
Klaus
When the LM393 output goes high =>
Try tying a 10kΩ resistor from the base of the transistor to ground.Does any of you know how to avoid this click sound?
That did the trick crutschow. Thank you!Try tying a 10kΩ resistor from the base of the transistor to ground.
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