How to take 10samples per second of an input in MIKROC?

jayanth.devarayanadurga said:

Use a for loop which loops from 0 to 9 and each time it should assign the adc value to a array with 10 elements. finally add the 10 elements and divide it by 10 to get the average value.

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swethamenon said:

Im planning to do project in MIKROC..dc energymeter..
For that i plan to take 10samples per sec of voltage and current and want to take average of that..is it possible in MIKROC?

im new to this..what to do to get this?

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bigdogguru said:

You should be able to implement a timer interrupt and ISR which can be configured to start an ADC every tenth of a second.

An interrupt and ISR also can be used to store each conversion value upon completion.

Effective use of interrupts and ISRs should allow the code to perform the required tasks on the ADC values in between handling the interrupts.

BigDog

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jayanth.devarayanadurga said:

I want to know whether you are using PIC16 or PIC18 before writing the timer routine.

This is the code for PIC16 4 MHz 10ms Timer. To get 100ms you have to use a counter which counts on every 10 ms timer interrupt overflow. If the count becomes 100 then it means 100 * 10 ms = 1000 ms = 1 sec. You have to take ADC samples on every 100th count. For 1000 counts you will have 10 samples of adc. take average of 10 samples and you will have the reault.

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Code C - [expand]
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//Timer0
//Prescaler 1:64; TMR0 Preload = 97; Actual Interrupt Time : 9.986 ms
 
//Place/Copy this part in declaration section
void InitTimer0(){
  OPTION_REG     = 0x85;
  TMR0       = 97;
  INTCON     = 0xA0;
}
 
void Interrupt(){
  if (TMR0IF_bit){ 
    TMR0IF_bit   = 0;
    TMR0         = 97;
    //Enter your code here
  }
}

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jayanth.devarayanadurga said:

Yes. It is for mikroC PIC16 4 Mhz clock. If you are using different clock mention it. Which PIC16 are you using?

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