amnakhan786
Junior Member level 3
- Joined
- Dec 30, 2009
- Messages
- 28
- Helped
- 0
- Reputation
- 0
- Reaction score
- 0
- Trophy points
- 1,281
- Location
- pakistan
- Activity points
- 1,493
Hi,
I am a beginner in vhdl, struggling with vhdl programming. I am currently reading books and trying to understand code by other authors. i have to understand a code structure like this:
my question is:
1)how this code will work, for behavioral part all statements execute concurrently, but signal_4 depends on signal so will second when-else would wait for signal computation?
2) how inport would be computed, concurrently or sequentially?
3)are all when else for signal computed simultaneously?
4)if i want to count how many bits of signal are turning to '1' after all 4 bits are computed is the 1's counter after when else for signal is the only way to do it? can i somehow count 1's within the when else?
5) if i want the same number of bits to go high for signal and signal_4, how can i do it?
I appreciate any help.
thanks
I am a beginner in vhdl, struggling with vhdl programming. I am currently reading books and trying to understand code by other authors. i have to understand a code structure like this:
Code:
entity declaration
architecture behavioral of entity is
signal declarations:
signal(0) <= '1' when signal_1(0)='0' and signal_2(0)='1' else '0';
signal(1) <= '1' when signal_1(1)='0' and signal_2(1)='1' else '0';
signal(2) <= '1' when signal_1(2)='0' and signal_2(2)='1' else '0';
signal(3) <= '1' when signal_1(3)='0' and signal_2(3)='1' else '0';
inport <= data_in and not signal;
signal_4(0) <= '1' when signal(0)='0' and signal_2(0)='1' else '0';
signal_4(1) <= '1' when signal(1)='0' and signal_2(1)='1' else '0';
signal_4(2) <= '1' when signal(2)='0' and signal_2(2)='1' else '0';
signal_4(3) <= '1' when signal(3)='0' and signal_2(3)='1' else '0';
inport_1 <= signal or signal_4;
process(clk)
do something here
.
.
end process
end behavioralmy question is:
1)how this code will work, for behavioral part all statements execute concurrently, but signal_4 depends on signal so will second when-else would wait for signal computation?
2) how inport would be computed, concurrently or sequentially?
3)are all when else for signal computed simultaneously?
4)if i want to count how many bits of signal are turning to '1' after all 4 bits are computed is the 1's counter after when else for signal is the only way to do it? can i somehow count 1's within the when else?
5) if i want the same number of bits to go high for signal and signal_4, how can i do it?
I appreciate any help.
thanks