how to obtain the laplacian in cylindrical coordinates?

Status
Not open for further replies.

gjfelix2001

Junior Member level 2
Joined
Oct 5, 2005
Messages
20
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,281
Activity points
1,359
i need a hint to obtain the laplacian in cylindrical coordinates. Thnkx
 

x=r*cos(θ), y=r*sin(θ).
Then use chain rule:
du/dx=(du/dr)*(dr/dx) + (du/dθ)*(dθ/dx)
du/dy=(du/dr)*(dr/dy) + (du/dθ)*(dθ/dy)
and then the second derivatives ...

Δu=(1/r)*d(r(du/dr))/dr +(1/r²)*d²u/dθ² +d²u/dz²
 
Status
Not open for further replies.

Similar threads

Cookies are required to use this site. You must accept them to continue using the site. Learn more…