Oct 5, 2005 #1 G gjfelix2001 Junior Member level 2 Joined Oct 5, 2005 Messages 20 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 1,359 i need a hint to obtain the laplacian in cylindrical coordinates. Thnkx
Oct 6, 2005 #2 M main_road Newbie level 6 Joined Oct 3, 2005 Messages 13 Helped 3 Reputation 6 Reaction score 0 Trophy points 1,281 Activity points 1,438 x=r*cos(θ), y=r*sin(θ). Then use chain rule: du/dx=(du/dr)*(dr/dx) + (du/dθ)*(dθ/dx) du/dy=(du/dr)*(dr/dy) + (du/dθ)*(dθ/dy) and then the second derivatives ... Δu=(1/r)*d(r(du/dr))/dr +(1/r²)*d²u/dθ² +d²u/dz²
x=r*cos(θ), y=r*sin(θ). Then use chain rule: du/dx=(du/dr)*(dr/dx) + (du/dθ)*(dθ/dx) du/dy=(du/dr)*(dr/dy) + (du/dθ)*(dθ/dy) and then the second derivatives ... Δu=(1/r)*d(r(du/dr))/dr +(1/r²)*d²u/dθ² +d²u/dz²