hi IanP,IanP said:I think you should use RMS-to-dc conversion and then use formula to calculate efficiency.
IanP
thanks for ur detail reply.You measure the average values, regardless of the operating mode. Even if the INDUCTOR current is discontinuous, both the input and output currents are continuous. That is because the capacitors will make these currents continuous, by supplying energy (current) during the time the inductor current is zero.
AndrzejM said:in my opinion everything is OK
there is a small misprint in (4):
≠[∫Io(t)dt ]*[∫Vo(t)dt ]/[∫Ii(t)dt ]/[∫Vi(t)dt ] ........(4)
your intention was probably to write "*" instead of "/"
≠[∫Io(t)dt ]*[∫Vo(t)dt ]/[∫Ii(t)dt ]*[∫Vi(t)dt ] ........(4)
Generally not. It's true, if I and V have the same waveform.But as far as I know the average power P=Irms*Vrms.
FvM said:Generally not. It's true, if I and V have the same waveform.
FvM said:P1 is the correct expression for the power consumption with arbitrary current and voltage waveforms, could be extended to
multiple circuit terminals if necessary. P3 is correct for a constant voltage and obviously equal to P1 in this case.
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