Thanks for your response Sir.
I have simulated the circuit that way and I have some questions now.
This is the efficiency graph of my circuit.
Is this efficiency looks good?
I guess it's simply diode breakdown. 50 % efficiency at 10 dBm input power refers to about 16 V DC output across 50k load, far beyond the useful diode voltage range, see BV of 3.8V. Real schottky diodes will be probably destroyed in this operation. In so far the circuit parameters don't seem well considered.
Question is how you arrived at the present circuit parameters like input power range, load resistance, diode selection? The circuit can't be safely operated as is, you either need to reduce the load resistance, restrict the input power or use a diode with higher breakdown voltage. I understood that this is an exercise problem without an exact application background, but there should be a consistent specification nevertheless.
This circuit is the rectification circuit of an of RF energy harvester, The WiFi signals will be captured and then will be rectified. The selected Parameters Are for RF, I mean Schottky diode is used because it is the diode which work at high frequencies, all other components values like capacitors and inductors values were get by optimizing the circuit in ads.
Here is how the optimization was done.