In this problem, the given number is located at 8000H location. After finding the 1’s
complement and 2’s complement the result locations are 9000H and 9001H respectively.
Subtract FD from FF to get the 1's compliment ( 00000010 ), and add 1 to the 1's complement to get the 2's complement ( 00000011 ).
Uses the add and subtract instructions, but not compare accumulator instruction ( CMA).
Subtract FD from FF to get the 1's compliment ( 00000010 ), and add 1 to the 1's complement to get the 2's complement ( 00000011 ).
Uses the add and subtract instructions, but not compare accumulator instruction ( CMA).