how to extract resistance from IV graph in origin

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aapirzado

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Hi All,
I need to know how one can extract the value of resistance from IV graph in Origin. I just plotted V and I on x-axis and y-axis respectively. I wonder there is some easy way to extract the resitance?
Thanks is advance,
 

say attached figure
say we have VI plot
Resistance (Impedence) = volt / current
so for our graph
this is similar to take slope
R = Delta V/ Delta I
Delta V = v2 -v1
delta I = I2 - I1
where I1 and V1 for the same point 1
and I2 and V2 for the same point 2

for the figure attached
resistance =( v2 - v1)/(I2 - I1)
= (4-2) / ((2-1)*10^-3) =2000= 2Kohm
as current is plotted in Milli Amper (mA)
 

put the current in the X-axis and the voltage in the y axes. then take the slop of the line which is I/V and this represents the resistor value

aapirzado said:
Hi All,
I need to know how one can extract the value of resistance from IV graph in Origin. I just plotted V and I on x-axis and y-axis respectively. I wonder there is some easy way to extract the resitance?
Thanks is advance,
Click to expand...
 

Junus2012 said:
put the current in the X-axis and the voltage in the y axes. then take the slop of the line which is I/V and this represents the resistor value
Click to expand...

I*R= V --> R= V/I
Slope = Rise / Run --> y/x
 

off course it is shown in the attached schematic .... R = V/I
 

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