Re: how to determine wattage for resistor with different current profile?
Hi,
in post #1 you say 12V...
But after I read post#7 I assume the 12V is never seen by the resistor.
Then this 12V value is irrelevant for resistor wattage calcutaion.
The power dissipation in the resistor is: P = I x I x R
This is true for RMS current (it is calculated of a dedicated period of time) as well as
for instantaneous current.
The peak current is 70A.
The RMS current for the given waveform is somewhere below 4.5A for the given waveform.
Now if you decide to dissipate not more than 1W during this time. then R = P / (I^2) ... about 5mOhms
This 5mOhms is for constant current, but in times with high current the resistor will temporarily overheat.
Therefore I recommend to use a 2W rated resistor. Then you have 1W of headroom for the current peaks.
Calculate peak pulse power dissipation: 70A x 70A x 0.005 Ohms = 24.5W
RMS pulse current for the first 1ms (70A linearily down to 4A in 1ms) = about 45 A --> P = 10W
All other values are more relaxed..
Now take the datasheet of a 2W, 0.005 Ohms resistor and look at the SOA graph.
Not all datasheet show this chart, but at least pulse load rated resistors should have.
Here an example of a 1W 0207 pulse rated MELF resistor (Vishay, CMB0207)
On the right side it shows the 10W limit (red circle)
For the very peak (1us) it shows more than 1000W
--> you are relaxed with your 24.5W
and for the 1ms limit it shows about 300W.
--> here also you are very relaxed with your 10W.
****
Please don´t port this result to standard resistors (non pulse load resistors).
Use a resistor that shows an SOA chart in it´s datasheet, then you can rely on that.
Klaus