how to convert array to integer value in pic c

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raman00084

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char gps_buf[]={"GPGGA,000044.262,,,,,0,0,,,M,,M,,*4E"};

in the array the last 2 characters is the check sum value ( 4E)

HOW CAN I CONVERT THE LAST 2 CHARACTERS TO DECIMAL VALUE
FOR EXAMPLE
CHAR CHECK_SUM[3]={0}
CHECK_SUM[0]='4';
CHECK_SUM[1]='E';

HOW TO CONVERT THIS TO DECIMAL VALUE THAT IS 78
if the valued are in the range of 0 to 9 then i can use atoi but one value is in hexadecimal
KINDLY HELP.
 

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Hexadecimal is base 16 so take the ASCII value of each character, subtract '0' to bring the ASCII value down to units then if the result is more than 9 (meaning it was A-F) subtract an extra 7. Then multiply the first character by 16 and add the second character.
Code: 
char DecimalChecksum = 0;
CHECK_SUM[0] -= '0'; if(CHECK_SUM[0] > 9) CHECK_SUM[0] -= 7;
CHECK_SUM[1] -= '0'; if(CHECK_SUM[1] > 9) CHECK_SUM[1] -= 7;
DecimalChecksum = (CHECK_SUM[0] * 16) + CHECK_SUM[1];

Brian.
 
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Just change the variable to hold the result to an 'int' because with 4 characters the value can be higher than a char variable can hold.

Then add the lines:
CHECK_SUM[2] -= '0'; if(CHECK_SUM[2] > 9) CHECK_SUM[2] -= 7;
CHECK_SUM[3] -= '0'; if(CHECK_SUM[3] > 9) CHECK_SUM[3] -= 7;

and change the final addition to:
DecimalChecksum = (CHECK_SUM[0] * 4096) + (CHECK_SUM[1] * 256) + (CHECK_SUM[2] * 16) + CHECK_SUM[1];

Note that if you are doing this many times in your program it might be easier to use the sscanf() or strtok() functions but they might use up a lot of additional program memory.

Brian.
 

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Hi,

please don´t shout in this forum = don´t use all capatial letters. Read forum rules.

****

Generally:
You don´t want to convert an "array" into an integer. Because "array" just means "multiple" of a variable.
But the variable of an array can be of any variable_type. (Char, int, float, signed or unsigned ...)

What you want to do is: Convert ASCII to binary.
You are not the first one. Thus an internet search gives me more than 16 million results.
(Now we have an additional one...)

Klaus
 

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