Re: switching energy?
The gate resisitor has no effect on the energy required to switch the MOSFET on and off. Only the MOSFET's switching speed will change and that will affect the MOSFET's switching losses, but that is entirely different from the gate drive energy.
To calculate the required gate drive power, look at the gate charge curve for your MOSFET. Read off the chart the gate charge at the maximum Vgs that you will be driving the MOSFET with. If you are driving it with 5V, see what the gate charge is at 5V; for 10V drive, go further up on the curve and find the corresponding gate charge for that drive voltage.
So now you have: Pg=Qg*Vg/Tsw=Qg*Vg*fsw
This is the power required for the gate drive, REGARDLESS of the value of the gate drive resistor. Simply because you need to supply it to charge the gate to the same voltage every time. And then you discharge the gate, losing that energy.
It is true that more of it is dissipated in the resistor and less in the driver transistors, if the resistor is larger. But the total power required to drive the gate is the same.