how to approximately solve this equation?

[shafee001]

how to approximately solve this equation?

 

[VSMVDD]

there is no way to 'approximatly' solve any equassion
you either solve it or not

the above calculations isnt an equassion

it contains no equators only pure maths

so.. any good calculator will solve it easy
do it one set of brackets at a time
then multiply all answers from left to right

the best way to solve the highorder powers
is to use a good quality piece of software like mathlab
it will allow large powers ... and give a sensible answer {very accurate}

 

[shafee001]

thanks for your comments
but i still know how to get the answer of it
matlab, mathmatica, calculators gives overflow error
it's a huge calculation, that's why i asked for approximitly? there may be an algorithm which i don't know it can solve? so i am still wondering?

 

[VSMVDD]

ok if you still get overflows this is easy

just take the power and /1000
so forinstance 9646 becomes 9.646
so this would be
10E9.646 etc...

then each stage you miltiply your answers simply add the right number of zeros to your final answer 12 zeros in total need added anyway....

this calculation can be done easier on paper than machines
its realy easy to do this longhand

 

[echo47]

In what numerical format do you expect the result? To print it out using ordinary scientific notation, the universe isn't big enough to hold all the exponent digits, even using a really small font.

 

[VSMVDD]

hahahahaha lol:¬))))

 

[zorro]

Let’s call x the number of your expression. Work with logarithms (for convenience, with decimal logs):

Log(x)=(5.53*10^9861)*Log[] .... an so on ....
Log(x)= (5.53*10^9861) * (1.15*10^9866) * (8.65*10^9862) * Log(1.42*10^9864)
Log(x) = (5.53 * 1.15 * 8.65) * 10^29589 * (Log(1.42) + 9864)
Log(x) = 5.42… * 10^29594

Thus, x is a really huge number. (Yet Log(x) is really huge!)
By comparison: Nowadays, the total number of particles in the universe has been variously estimated at numbers from 10^72 up to 10^87.
Where does this question come from?

Regards

Z

 

[VSMVDD]

maybe the guy needs the big house ?

but its a serious calculation so a / by 1000 powers all over and move the decimal point is the best method


if you like my pal ill calculate the answer on paper and scan the workings...
if you like?