How Thevenin theorem work in BJT circuit

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Awalluddin

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Hi guys, as you know a typical bjt circuit how the circuit converted from single voltage source into two voltage source? I understood the Thevenin theorem and the calculation. But I couldn't connect the dot how a single voltage source change to two voltage source. I cannot map my previous knowledge and as you know university dont give a "something" to really teaching. The picture just to depict the transformation the value dont matter.
220px-Voltage_divider_bias.svg.pngimages.png
 

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In that circuit, static DC circuit, you can write the BJT equations.

Page 97-99 of attached.


Regards, Dana.
 

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Hi,

If I understand correctly:

You want to transform the 10V source with 47k ... to a voltage divider supplied by 20V?

First question needs to be:
If we have a 10V source connected to a 47k ...and we draw no current:
What would be the expected output voltage?

So basically - without part calculations - how can we get the same voltage from a resistive divider? (again no current drawn)

Klaus
 

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Awalluddin - I must admit that I do not understand your problem. Example: What is the relation between both circits?
What really is your question?
 

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R1 and R2 is the same as a fixed example of a potentiometer with the equivalent resistance at the tap being set to 50% from 20V. The pot would approximately be 100k, but in this case 47k*2.
If you want more info, this topic is well covered in web searches, if you care to look.
 

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