So it's good in terms of the waveform? I want to output to be the square waveform either, should I increase the bandwidth?By nature of bandpass filter, if the input waveform is a square wave, the output waveform will be different. Not clear what you want to achieve.
Just want to use a cap-based amplifier, should I increase the BW? Because I want to let the circuit work on 1MHz and without too much noiseare you using a filter at all
Thanks, could I move this high f to a higher freq so it has a better output performance? Also, is there any recommendation for the high-frequency circuit structure?The whole point of a bandpass filter is to attenuate low and high frequencies. There's no way you can expect fast edges AND attenuated high frequencies. Fast edges=high frequency.
A comparator with 80nS rise time isn’t going to give a very good square wave at 1MHz.I suggest a low-pass filter to remove high frequency noise (if needed), followed by a high-speed analog comparator (for example MCP6566) to generate a good square-wave.
The propagation delay of that comparator is 80ns, but the rise-time is basically determined by the pull-up resistor value and stray capacitance.A comparator with 80nS rise time
Thanks for your reply; I think I need to tune the bandwidth for the circuit (I want a high-pass filter that can amplify my signal; BTW, do you also have any ideas for the question below?The propagation delay of that comparator is 80ns, but the rise-time is basically determined by the pull-up resistor value and stray capacitance.
The fall-time is 20ns.
Thanks for your reply, I wonder if I can use a high pass filter so the square waveform can be passed better?what “noise” are you trying to filter? Maybe you just need a low pass filter, not a band pass. with zero requirements it’s impossible to give an intelligent answer. what’s your rise time requirement? what’s your pass and tprequirement?
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