How do you convert MHz to Mbps?

[suhas_shiv]

I have a simple question. How do you convert MHz to Mbps?
Say for example I have a LVDS receiver operating at 400Mbps, so is the operating frequency 400MHz or 200MHz? The reason I ask is that some company products specify the working frequency as 200MHz while the data rate is 400Mbps. I am a little confused.

thanks

 

[IanP]

Re: Simple Question

(X bits * Y Mhz) / 8 = Z Mbps

...

Assuming there are 8 bits in a byte:
(megabits/second) / 8 = megabytes/second

It looks as though your numbers are not coming out correct because different busses have different number of bits/byte. Some are 8 bits/byte so you would divide by 8, others have 10 or 11 bits per byte.

Also keep in mind that for base 2 there are 1024 bits in a kilobit, while in base 10 there are 1000 bits in a kilobit. I believe that modems use the metric base 10.

Also, see: https://en.wikipedia.org/wiki/List_of_device_bandwidths

Regards,
IanP

 

[suhas_shiv]

Simple Question

I think megabits/sec is Mbps and megabytes/sec is MBps.

 

[Fawad Elahi]

Simple Question

each cycle has two peaks. if the positive peak is represented by level 1. and the negative peak is represented by level 0.
then the bits rate is double than the bandwidth of the channel

 

[Eugen_E]

Re: Simple Question

Considering it's about baseband transmission - no modulation, it depends on the coding. More exaclty, it depends on the period of the shortest signal element. The data being random, it's a bandwith, not a single frequency.

If NRZ coding is employed, for a bitrate of X bps, the signal spectrum will have a peak at X/2 Hz. The spectral energy will ocupy an theoretical unlimited - but in practice limited bandwidth, since the data is random.
For Manchester/Biphase coding, bitrate X bps, the signal spectrum will have a peak at X Hz.
For multilevel coding (rarely used, egg. fast Ethernet), the significant spectrum portion can be less than X/2 Hz, as the number of levels is increased from 2 up.