How can I derive the sin of a angle

Highlander-SP · Dec 13, 2005

What is the d/dt sin Θ ?

manenef · Dec 13, 2005

The answer to your equation would be zero, because θ is not a delivative of d/dt.. otherwise if it were d/dθ sinθ, the answer would be cosθ.
goodbye

kivet · Dec 13, 2005

Hi,

in your problem it seems sinθ is not a function of time (if t is time). therefore the derivative of sinθ with respect to t is zero.

Highlander-SP · Dec 14, 2005

but Θ isn't a function ωt?

ω (rad/sec) * t (sec) = Θ (rad)

kivet · Dec 14, 2005

Hi,
Because θ is a function of time (t) then d/dt(sin ωt) = ωcosωt.
The derivative of sine is cosine.

mtkee2003 · Dec 14, 2005

hi

in general

if θ = θ(t) then d(sin(θ(t)))/dt is equal to:

(d(θ(t))/dt) × cos (θ(t))

have a nice day