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Are the currents and R values, as shown in right hand pic the "givens" ?

If so the node V is simply Vnode = 9V - 1.76 mA X R1.......

But to use V divider you need the equiv R at Vnode. Using above Vnode, and you know the total

current going into the complex part of the network, you have -

Requiv = Vnode/1.76 mA.....

But if you want to do the derivation of Requiv, FVM would be the way at getting at Requiv, has

the advantage of not needing any I's, just Vsource (9V).....