I hope so. But for the sake of clarity you should really show a diagram of expected output versus input voltage, or may be a table.you get what i want to do.
this is input output relations ,below 2 volt the input is doubled and greater than 2 volt the output is equal to the inputI hope so. But for the sake of clarity you should really show a diagram of expected output versus input voltage, or may be a table.
So when the output is 1V you don't care whether the input is 0.5V or 1V since they both would give the same output?this is input output relations ,below 2 volt the input is doubled and greater than 2 volt the output is equal to the input
i had another idea to solve this issue , using microcontroller if signal is less than 2 volt it will be amplified then Q2 will be switched on to pass it .if the signal is greater than 2 v Q1 sitched on and pass it .this is input output relations ,below 2 volt the input is doubled and greater than 2 volt the output is equal to the input
no i didn't say that, every value below 2 volt should be doubled and that mean when te output is 1 the input should be only .5vSo when the output is 1V you don't care whether the input is 0.5V or 1V since they both would give the same output?
So with a 1.99V input, the output will be 3.98V, but when the input is 2V, the output will be 2V? So if the output is 3V how will you know whether the input is 1.5V or 3V since either of those inputs can generate a 3V output??.............................
no i didn't say that, every value below 2 volt should be doubled and that mean when te output is 1 the input should be only .5v
aha , i got you . i don't know how to differentiate between them,but the circuit that i proposed don't need this informationSo with a 1.99V input, the output will be 3.98V, but when the input is 2V, the output will be 2V? So if the output is 3V how will you know whether the input is 1.5V or 3V since either of those inputs can generate a 3V output??
No the circuit doesn't but do you need to differentiate between them when you are observing the output?aha , i got you . i don't know how to differentiate between them,but the circuit that i proposed don't need this information
i don't need to differentiate between them if the operation in the table is done. the output is used to be input for inverter that drives motorNo the circuit doesn't but do you need to differentiate between them when you are observing the output?
What are you doing with the output?
aha , i got you . i don't know how to differentiate between them,but the circuit that i proposed don't need this information
And this inverter/motor won't mind the step transition in voltage when the output suddenly switches gain?i don't need to differentiate between them if the operation in the table is done. the output is used to be input for inverter that drives motor
what is the value for v1 and v2 and what do you mean by E2 is op model. and how to modify the trnasition voltage from 2 v to any other like 1volt?. please clarify connections.This simple circuit might work as a practical solution. The voltage source E2 is an OP model.
No, you can't replace the PNP with an NPN. Why would you want to?could i replace the pnp by npn and reverse collector and emitter connections? . i did your cisrcuit in proteus but the output greater than 2 is less than input and ithis difference increased with increasing input.
i know that the base polarity should be changed with npn but i didn't completely get you, do you mean that my attempt to do the circuit is useless .Base voltage polarity matters, thus you can't use a NPN transistor in this circuit. It's up to you to design a circuit that can use NPN transistors, according to your previous results how many attempts do you expect?
I must admit that my interest is slowly fading...
Happy developing!
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