Hi Rihanna
By "path", I assume you mean the distance between the satellite and the earth station. In that case the first equation would be perfectly accurate if the world was flat, as shown in the diagram below.
Unfortunately, the world isn't flat so that equation doesn't work very well. Playing around in a spreadsheet, it seems like it's not only very inaccurate for low values of theta, but also if the satellite is too high. e.g. For a geostationary satellite, hs= 35,786 kilometers, and that equation is nowhere near accurate even for theta = 30 degrees (assuming I managed to figure out the correct answer).
Unfortunately the second equation you gave is wrong too. Maybe you made a mistake copying it or maybe I made a mistake in the spreadsheet, but either way I don't get good answers with it.
As best as I can figure it out, the correct equation is:
Path = 0.5*(-B+(B^2-4*C)^0.5)
where:
B = 2*Re*SIN(theta)
C = -((H+Re)^2-Re^2)
where:
H = height of satellite above ground
Re = radius of earth = 64000km, not 85000km
I ignored he, assuming the earth station is at ground level.
Cheers - Godfrey