Help Required for step up autotransformer

Dear Rfredel Sir,

I am from India and i am new in transformer calculation as on 27.04.2013 i join myself to edaboard.com. i have read a lot of books also see many articles over the internet during this time rewind many transformer but at last while read your article which was for step down autotransformer i am satisfied. i always honor to Germans technology also. sir i want the same article for a step up autotransformer i will be highly obliged for same. here is attached of your step down autotransformer page.

**broken link removed**

In this article i want to understand some item. as follows.
1. Power of a normal transformer P=(Fq / B)² why B value is 1.3 ( i understand core is CRGO ) ?
2. P auto transformer = P normal transformer / {1-(U2/U1)} here is U2 = output volt & U1 is input volt what will be calculation for step up autotransformer ?
3. N/V = 10*10*10*10 / (4.44 * 1.3 * 11.52 * 0.9 * 50 ) what is meaning for 0.9 filling fector ?

the filling factor in the turns per volt, or volts per turn calculation refers to the density of the iron transformer core.

often the density is included in the manufacturer's flux density limits.
if the iron is 10% oxide and varnish in the form of insulation between the layers of iron, then the filling factor would be .9

Dear Johansan sir,

can u explain article or mail me elanshul@gmail.com for a step up autotransformer as rfredel explain for step down auto transformer. i will be highly obliged.