tanmoykar
Newbie level 5
help related to CRC -8
Can any one help me regarding CRC-8? Now i came accross a CRC-8 implementation : According to this
generator polynomial x^8+x^2+x+1 with procedure
1)All 7 bits over which CRC will be applied, are complemented and become the coefficients of a polynomial, M(x), of degree 6,
2) the remainder, R(x), is calculated from [(M(x) * x^8 + x^7)/G(x)],
3) R(x) is complemented to become the CRC.
Can any one please explain me why X^7 is added? As any other CRC defination includes only 1st part (M(x)*x^8)/G(x). This document provides the reference of ANSI x3.66-1979.but i didn't find this document. Can any one please provide me this document?
Can any one help me regarding CRC-8? Now i came accross a CRC-8 implementation : According to this
generator polynomial x^8+x^2+x+1 with procedure
1)All 7 bits over which CRC will be applied, are complemented and become the coefficients of a polynomial, M(x), of degree 6,
2) the remainder, R(x), is calculated from [(M(x) * x^8 + x^7)/G(x)],
3) R(x) is complemented to become the CRC.
Can any one please explain me why X^7 is added? As any other CRC defination includes only 1st part (M(x)*x^8)/G(x). This document provides the reference of ANSI x3.66-1979.but i didn't find this document. Can any one please provide me this document?