question: a 6 bit 2 GSamples/s flash A/D converter with Vref = 1V. It uses an array of preamplifiers followed by a comparator array.
(a)The comparator can resolve a 50mV difference at its input to full logic levels at its output. What is the gain required in the preamplifiers?
soution:VLSB=Vref/64=15.6mV,minimum input to preamplifiers=VLSB/2,which must be amplify to 50mV. So gain=6.4
i am confused why minimum input to preamplifiers=VLSB/2. if vin=15mv, the input to the first preamplifiers is just 15.6-15=0.6mv<<15.6/2 mv,right? [/img]