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Re: Help needed :how to calculate the vout for the given cir
I'll give you a hint to get you started.
First break this down into two problems.
1.) You have to calculate the DC offset part of the problem.
-Start by ignoring the AC power source. Short it out.
-We know the voltage at a couple nodes below the bottom 50k resistor is -15V (Let's call it node A). The top of the top 50k resistor is +15V (Node B). Hopefully you know why.
-Use voltage division to find the voltage at the nodes at your two output lines. This is particularly easy in this case because you have the same resistors above and below the center point where you shorted the AC. That makes this the half way point and as such you can draw a tie to ground where you had your AC source. So Node A = -15V, Center point is Ground or 0V and Node B = +15V. Your lower output is thus 0 - 1/(50+1)*15 approx -0.29. Your higher output is 0 + 1(50+1)*15 approx +0.29. So that gives you approx 0.58 across the output in DC.
2.) If you can figure out how to add your AC to that, then you're done.
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