help me to charge the capacitor in random signal

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masterminocha

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help me

I have a ac signal that is a random signal..but if u check it using the multimeter the output comes out to be 10 volts rms. Now i have four such signals that i add up. But now my problem is to charge a capacitor rated rated 5 v using these four added signals that may round up to be 40 volts rms..if i m not wrong..can any one help me to charge the capacitor rated 5 volts from around 30-40 volt rms?..
 

help me

Hi,
maybe apply pls a charge current_with serial resistors limit the currents from the sources & connect a 5V zener onto the charged cap.?
Added random signals are not 40V, you must calculate with random phase angles/voltage values too...
(otherweise their arent random signals, maximum statistically coming , but with same frequency and phase)
K.
 

random signal in this case means the signal is not perfect ac..
yes you are right they wont add up to 40 rms
but the combined rms after rectification is coming out to be..25 volts
but i need only 5 v without wasting the energy..as if i m reducing the voltage the current should increase keeping the power same..now i think i explained it in a better way..so i think zener wont work here..not even linear regulators..
 

As far as I understand the problem description, a rectifier and a step-down converter would do. "Charging a capacitor"
isn't actually a clear specification, however.
 

to charge a super capacitor of 5V and 5F i need to design a dc dc step down converter but how???
 

Possibly a usual integrated buck-converter, e.g. National "SimpleSwitcher" can do. As another important parameter, you should
specify the intended/allowed load current respectively capacitor current.
 

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