mobinmk
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i cant understant frm the lm339 comparator.
dc reference voltage by resistors fed into 3.3v??
output of comparator is connected with 2 resistor.in middle point =3.3v
why this 2 resistor is connected across the output of comparator.?
LM339 doesn't have an internal pullUp, so it needs an external one (s. LM339 dataSheet).
The circuit is incomplete. CD4011 power supply is missing.
CD4011 GND must not be isolated from comparator ground. CD4011 input high level must be 70 percent of it's supply voltage, this can be achieved by connecting the pull-up resistors to the CD4011 supply. The circuit doesn't work without pull-up resistors.
The circuit is incomplete. CD4011 power supply is missing.
CD4011 GND must not be isolated from comparator ground. CD4011 input high level must be 70 percent of it's supply voltage, this can be achieved by connecting the pull-up resistors to the CD4011 supply. The circuit doesn't work without pull-up resistors.
The DDS link finally clarifies how you arrived at the circuit in post #1.
Unfortunately it's the wrong attempt to make a motor inverter. In stead of low pass filtering the pwm output, it would be directly send to the power stage. Appropriate logic must provide dead time for the gate signals, avoiding simultaneous on-state of high and low side transistors.
A side node about opto coupler. PC817 is a slow optocoupler with many µs rise and fall time and respective delay and delay skew. You need a fast optocoupler with logic gate output and MHz speed.
The duty cycle is primarly defined by the sine waveform. I guess you want to change the sine magnitude, but this should be done by a multiplication in the arduino software. Please consider that a proportional v/f characteristic should be implemented, don't apply full voltage at low frequency.
Regarding not-gate usage. The gate signals for low and high side driver are basically complementary. But you need assure a certain dead time between low and high side on-state. Some gate drivers have build-in deadtime, it can be also achieved by assymetrical gate circuits (resistor + diode) or by an asymmetrical delay with a RCD circuit in front of the driver IC.
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Optocoupler: e.g. Sharp PC400, PC410, Toshiba TLP109, TLP118, many vendors 6N137
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Now the +ve terminal of IC1C & IC2A is connected to the IC1A.
BUT the -ve terminal of IC1D,IC2B is jus short each other, Any mistake there ??
I think that -ve terminal of IC1D,IC2B is connected to IC1B ?? "
You have added a missing connection, but the overall circuit still makes no sense to me.1) is this modifed circuit is correct ?
You have added a missing connection, but the overall circuit still makes no sense to me.
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