Dec 9, 2005 #1 B brahma Advanced Member level 4 Joined Sep 29, 2005 Messages 109 Helped 15 Reputation 30 Reaction score 1 Trophy points 1,298 Activity points 2,191 u(t) = 1 for t>0 how to prove u²(t) =1 for t>0.
Dec 10, 2005 #2 P pthoppay Member level 4 Joined Nov 6, 2005 Messages 79 Helped 6 Reputation 12 Reaction score 2 Trophy points 1,288 Activity points 2,122 Re: step pulse Hi, I dont see any complication here, wont just squaring the wave at all values of `t` do? Prakash.
Re: step pulse Hi, I dont see any complication here, wont just squaring the wave at all values of `t` do? Prakash.
Dec 11, 2005 #3 H hamidr_karami Banned Joined Oct 17, 2005 Messages 77 Helped 4 Reputation 8 Reaction score 3 Trophy points 1,288 Activity points 0 Re: step pulse hi, it's very simple to solve. you can u(t) multiply by u(t) in t>0 1*1=1 ==> u(t)*u(t)=u(t)
Re: step pulse hi, it's very simple to solve. you can u(t) multiply by u(t) in t>0 1*1=1 ==> u(t)*u(t)=u(t)
Dec 13, 2005 #4 B brahma Advanced Member level 4 Joined Sep 29, 2005 Messages 109 Helped 15 Reputation 30 Reaction score 1 Trophy points 1,298 Activity points 2,191 Re: step pulse so according to you u(t)×u(t) = 1 = u(t) so multiplication in time domain is equivalent to convolution in frequency domain. will this be satisfied????
Re: step pulse so according to you u(t)×u(t) = 1 = u(t) so multiplication in time domain is equivalent to convolution in frequency domain. will this be satisfied????
Dec 13, 2005 #5 purnapragna Advanced Member level 4 Joined Oct 21, 2005 Messages 107 Helped 6 Reputation 14 Reaction score 3 Trophy points 1,298 Activity points 2,287 Re: step pulse it is surely possibe!
Dec 13, 2005 #6 A Andrew10 Newbie level 4 Joined Oct 20, 2005 Messages 5 Helped 1 Reputation 2 Reaction score 0 Trophy points 1,281 Activity points 1,326 Re: step pulse Fourier transform for step function is the distribution (or general function), similar to Dirac function. Therefore you must calculate convolution for the two distributions. In this case you will obtain the correct result. Excuse me for my bad english!
Re: step pulse Fourier transform for step function is the distribution (or general function), similar to Dirac function. Therefore you must calculate convolution for the two distributions. In this case you will obtain the correct result. Excuse me for my bad english!