Gyrator simulated inductor design?

Status
Not open for further replies.
M

mr_monster

Member level 4
Joined
May 10, 2012
Messages
79
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,286
Visit site
Activity points
1,964
I would like to make a simulated inductor which is tune-able using an opamp implementation of an opamp. I could find a good source for the design process so anything like that would be greatly appreciated. Thanks!
 

Falstad's animated simulator includes a gyrator (active inductor) in its menu of circuits.

Screenshot:



Clicking this link will open the falstad.com website, load the above schematic, and run it on your computer. (Click Allow to load the Java applet.)

https://tinyurl.com/axjyjqz

You can change values by right-clicking a component and choosing Edit.

I don't know how to make it tunable.
 


Thanks for the link! However I did not see any formulas or anything on there? I would like to know how to set the inductor parameters using part selection... thanks!
 

Yes, I believe it works like this...

The upper schematic shows 250 nF & 20k (the resistor to ground). The capacitive time constant (R x C) comes out to .005.

The lower schematic shows 5H & 1k. The inductive time constant (L/R) is .005. This matches the upper example as to math and performance.

So for a given capacitor value in the gyrator, you can tune its effective Henry value by adjusting the resistor to ground.
 

mr_monster said:
I would like to make a simulated inductor which is tune-able using an opamp implementation of an opamp. I could find a good source for the design process so anything like that would be greatly appreciated. Thanks!
Click to expand...

As you will have noted - the circuit as given in post#2 is an active lossy inductor.
In case you need a lossless inductor you must use a GIC implementation using two opamps.
 

LvW said:
As you will have noted - the circuit as given in post#2 is an active lossy inductor.
In case you need a lossless inductor you must use a GIC implementation using two opamps.
Click to expand...

When you say lossless, you mean without series resistance? What would be a Q of such an inductor if that is even discussable in those terms? What about the Q of a simulated inductor? reactance / resistance?
I can make a tunable version by using a variable resistor instead of resistor going to ground?
 


"Lossless" means: Without resistive losses. Thus, under ideal conditions Q approaching infinity.
In reality - no opamp is ideal and, thus, no GIC implementation is ideal leading to a finite Q - however very large (depending on the opamp type and the operating frequency).
 

mr_monster said:
I would like to make a simulated inductor which is tune-able using an opamp implementation of an opamp. I could find a good source for the design process so anything like that would be greatly appreciated. Thanks!
Click to expand...

Here is another information which may be helpful for you:

There is another single-opamp active inductor with a parallel loss resistor (instead of a series loss resistor as shown in BradtheRad`s answer).
It is based on the integrator principle. If you are interested - give notice.
 

mr_monster said:
Sure I would like to see that!
Click to expand...

It`s quite simple:

Take the classical inverting MILLER integrator (R2, C2) and use another resistor R1 between opamp output and signal input (left node of R2).
Then you get an impedance Xp=(Rp||jwL) with Rp=R1||R2 and L=R1*R2*C2.
 

Status
Not open for further replies.

Similar threads

Menu
Log in
Register
Cookies are required to use this site. You must accept them to continue using the site. Learn more…