Feb 15, 2010 #1 K Kipster1203 Newbie level 1 Joined Feb 15, 2010 Messages 1 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 1,286 I know this might be cake for some of you but it's been a while for me... how would you find the series coefficients of a signal such as cos(2pi 500t)*sin(2pi 1000t) and of a square defined by x(t)=1 for 0<t<1, 0 for 1<t<2 and x(t) = x(t+2) Thanks for the help!!
I know this might be cake for some of you but it's been a while for me... how would you find the series coefficients of a signal such as cos(2pi 500t)*sin(2pi 1000t) and of a square defined by x(t)=1 for 0<t<1, 0 for 1<t<2 and x(t) = x(t+2) Thanks for the help!!
Feb 16, 2010 #2 M marzouki Newbie level 3 Joined Feb 16, 2010 Messages 3 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Location France Activity points 1,300 Kipster1203 said: I know this might be cake for some of you but it's been a while for me... how would you find the series coefficients of a signal such as cos(2pi 500t)*sin(2pi 1000t) and of a square defined by x(t)=1 for 0<t<1, 0 for 1<t<2 and x(t) = x(t+2) Thanks for the help!! Click to expand... For the first use: sin(a+b) +sin(a-b)= 2 sin(a)cos(b) For the second calculate the untegral by hands, it's very simple and obvious
Kipster1203 said: I know this might be cake for some of you but it's been a while for me... how would you find the series coefficients of a signal such as cos(2pi 500t)*sin(2pi 1000t) and of a square defined by x(t)=1 for 0<t<1, 0 for 1<t<2 and x(t) = x(t+2) Thanks for the help!! Click to expand... For the first use: sin(a+b) +sin(a-b)= 2 sin(a)cos(b) For the second calculate the untegral by hands, it's very simple and obvious