metal1,3,5 horizontal
metal2,4,6 vertical
metal1 is not usable, so if you have 5 layers, for routing resource, you have metal 2,3,4 5 available, i.e. the resource on horizontal direction (2 metal layers) and vertical direction (2 metal layers) is the same, and AR = 2/2 =1; if you have 6 layers, you have metal 2,3,4,5,6, which means vertical direction (2,4,6) has more resource that horizontal(3,5). If you make horizontal direction wider, ie. AR = 2/3, then you make the routing resource roughly the same for both directions. Make sense?