Feb 5, 2014 #1 E electronic_satya Member level 2 Joined May 17, 2011 Messages 49 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,286 Activity points 1,662 Hi, i am having this very elementary question. I have put the clarification in the attachment. Could someone please explain me. Thanks in advance, Regards, Satya Attachments clarify_KVL.pdf 89.1 KB · Views: 58
Hi, i am having this very elementary question. I have put the clarification in the attachment. Could someone please explain me. Thanks in advance, Regards, Satya
Feb 6, 2014 #2 barry Advanced Member level 7 Joined Mar 31, 2005 Messages 6,556 Helped 1,206 Reputation 2,424 Reaction score 1,435 Trophy points 1,393 Location California, USA Activity points 35,661 That looks right. It's a simple voltage divider. The way I would do this: I=V/(R1+R2) I=5/200=.025 Va=I*R2=2.5
That looks right. It's a simple voltage divider. The way I would do this: I=V/(R1+R2) I=5/200=.025 Va=I*R2=2.5