Re: Help please
hope am not posting this late..
you know that the rate of change of a certain quantity (f) in respect to another quantity (x) (where f is a function in x) is:
{f(x2) - f(x1)} \ {x2 - x1}
this is the rate of change of f when x changes from x1 to x2.
now if we want the rate of change for f at a certain x, we can simply take the limit of the rate of change as x2 goes to x1, as if we are making them a single point!
in your formula (a) is x2-x1, and by taking the limit as a goes to 0, you are finding the rate od change at a certain point x. and this is the definition of the derivative.
you find differentiation in problems that ask for rate of change because it is asking for the rate of change at a certain point! in your question he asked how fast (the rate of change of the height in respect to time)
when the water is 4 inches deep!
we differentiate distance to obtain the instantaneous speed at a ceratin time, cause by definition speed is the rate of change of the distance in respect to time, and it is instantaneous because it is at a certain time.
in your question you are given that the volume of the water is changing with respect to time by a rate 2/3 and you are asked for the rate of change of the height at a certain point, and you know the volume as a function in the height, so you simply differentiate both V and H in respect to time and substitute with the values.
you should understand what is the question asking for, and in respect to what you must derive.
good luck in your exam