Explain working of Positive clamper

Please explain the working of the unbiased Positive clamper circuit shown here.

**broken link removed**

From t0 to t1 the C charges to Vm say (Vm = Vi - 0.7V)

Vm is -10V for ideal diode.

Now Voltage from + side of C to gnd is +10V

Now Vi increases from -10 to 0V during t1 to t2

I want KVL for this condition that is when t = t1 to t2 (as diode anode is still +Ve and left side of C is still -Ve)

I have seen this referred to as the Villard cell. It is the building block for a class of voltage multipliers.

Notice if you attach a load across the capacitor, you would have an ordinary half-wave power supply.

In this case, however we attach the load across the diode. The diode displays a wide voltage swing (occupying one polarity, mostly).

The capacitor is a charge-pump. It is charged when current goes in one direction. When current goes the other way, the supply voltage is added to the capacitor charge. This boosts the volt level which is available for applying to a device.

Example, driving an led from an AC supply whose amplitude is less than the forward voltage of the led.



By adding a peak detector (diode and smoothing capacitor), it creates a voltage doubler. (As shown on page 2 following your linked webpage.)

Ok. What simulator are you using? Where can I get that simulator?

This is Paul Falstad's interactive animated simulator. Free to download and use at:

www.falstad.com/circuit