During the time the switch is off, the energy stored at the core (magnetizing inductor) is "recovered" or sent back to the source by means of the auxiliary reset winding. Is this correct?
Apparently the energy is reduced to zero as it circulates in the diode and the primary.
Explained at the website:
Quote: "During the off-time of the transistor, the magnetic flux of the transformer has to be reduced to zero. The transformer core is demagnetized with N1' via D1 to Vin."
(The names of the components are different from the Wikipedia article.)
But if the circuit is powered by a non-rechargeable battery, I don´t think that´s a good idea. How is it implemented in that case? I think a diode and large capacitor between the battery and the circuit will help (because one can recharge a capacitor, indeed), but really don´t know. Am I right?
From the above it does not appear that current would flow 'backward' either back to an installed capacitor or to the battery.
The website below is an article about converters that are suitable for battery power.
'Regulator Topologies for Battery-Powered Systems'
Quote from article:
"The buck regulator with a flyback winding is the superior-performance topology for many battery-powered applications. The configuration has excellent stability, low peak currents, and low output ripple."
The article points out that peak current is a chief concern when using battery power. If the battery has internal resistance, then the converter will be limited in its power capability.
Of course efficiency is also important when running from batteries.
As to which topology to use, it seems inevitable that there will be tradeoffs to consider. One type might be better for one reason, and another type might be better for another reason.