[ARM] Enc28j60 with STM32F4

[sainti]

Hello everyone, how we can link own monitoring website with ethernet controller having interfacing with stm32f4 project.

I just simply monitor the LED through web page on the browser by inserting a IP address like 198.168.1.119/page and this done by me on localhost(local network).
Now, i wanted to use my monitoring related website(i have it public ip and this website is server) with this project so how can i do this.

Actually, I am totally confused about whole project so i request you to please guide me .

should i learn socket programming for it or i have take separate training for IOT.

 

[Easyrider83]

You need to add 'Network Interface' to FreeRTOS TPC and add a ENC28J60 driver. I did that before and can give you my codes.
View attachment enc28j60.zip
But! F4 has it's own MAC which has a official FreeRTOS driver and support 100M speed. But if you need exactly this old spi phy, here you are.

 

[sainti]

Thank you Easyrider83 , please look @ the following link, and please tell me should i proceed according to this website for my web-based monitoring project.
https://mostlyprog.wordpress.com/2012/02/01/msp430-enc28j60-ethernet-part-2/

 

[Easyrider83]

First you need to make ethernet working with static ip and working ping
Next step is to process http request. Generate a simple html page is easy, but for live data ajax request have to be implemented. This is very advanced for now.

 

[Aussie Susan]

@Santi - this is the 5th thread you have started on this topic (https://www.edaboard.com/showthread.php?386256-Enc28j60-with-stm32f4&highlight=enc28j60, https://www.edaboard.com/showthread.php?386114-Enc28j60-with-stm32f4&highlight=enc28j60, https://www.edaboard.com/showthread.php?386107-Enc28j60-with-stm32f4&highlight=enc28j60 and https://www.edaboard.com/showthread.php?386014-stm32-interfacing-with-enc28j60&highlight=enc28j60 being the other 4).
All of the responses you have received so far are basically telling you the same thing .
What is it that makes you think that asking the same question over and over again will give you a different answer?
Susan