T
treez
Guest
Hello,
Do you agree that the huge 23Amp pk-to-pk circulating current in this sepic converter’s coupled inductor causes no hysteresis losses in the coupled inductor’s core?
So, -the following is a 7.5W coupled inductor sepic converter (Vin=5V, Vout=15V, f(sw)=104KHz, CCM).
Schematic (also pdf attached)
https://i40.tinypic.com/vfa2ht.jpg
The leakage inductance and the sepic capacitor have a resonant frequency of 104KHz, which is the same frequency as the switching frequency.
Due to this, there is an enormous, resonating, 23 Amp peak-to-peak circulating sinusoidal current which circulates through the coupled inductors and sepic capacitor.
However, would you agree, that this huge circulating current causes absolutely no hysteresis losses in the coupled inductor’s ferrite?, -and that this is because as it transitions through the primary, its magnetic field is oppositely polarised to the direction of the magnetic field that is produced as it travels through the secondary?
(in other words, the fields produced by this current cancel each other out, and so no hysteresis losses are produced.)?
Do you agree that the huge 23Amp pk-to-pk circulating current in this sepic converter’s coupled inductor causes no hysteresis losses in the coupled inductor’s core?
So, -the following is a 7.5W coupled inductor sepic converter (Vin=5V, Vout=15V, f(sw)=104KHz, CCM).
Schematic (also pdf attached)
https://i40.tinypic.com/vfa2ht.jpg
The leakage inductance and the sepic capacitor have a resonant frequency of 104KHz, which is the same frequency as the switching frequency.
Due to this, there is an enormous, resonating, 23 Amp peak-to-peak circulating sinusoidal current which circulates through the coupled inductors and sepic capacitor.
However, would you agree, that this huge circulating current causes absolutely no hysteresis losses in the coupled inductor’s ferrite?, -and that this is because as it transitions through the primary, its magnetic field is oppositely polarised to the direction of the magnetic field that is produced as it travels through the secondary?
(in other words, the fields produced by this current cancel each other out, and so no hysteresis losses are produced.)?