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Differential Output Current

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ebernz

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Hi guys, Need help on identifying or maybe confirming my equation on determining the differential output current (double ended) on this circuit.

Differential_circuit.jpg


Am I corrent?

Idiff(double ended) = 1/2(Ip-In)
 

As long as your circuit doesn't show a load and Idiff, it can't be answered unequivocally.
Also, if Ip and In are meant to be the transistor output currents, they should be drawn as such.
Furthermore, it's confusing to draw opposite polarity for Ip and In. In this case, Ip-In can't be correct.
 

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