If my sepic converter is designed to give 14v output at 8v input when duty cycle is set to 64%,can i measure the open circuit output voltage....?
or for 25v input is designed to give 14v output at 36% duty cycle?can i test open circuit voltage?
It is risky to run open output on any switched-coil converter, because it can result in unpredictably high volt levels (possibly in the hundreds or thousands of volts).
This can happen because the inductor has current running through it, then it is switched off suddenly so that it sees high impedance. A high voltage spike develops. It can be high enough to create a spark. If a spark occurs inside a lead-acid battery, it can ignite hydrogen gas, possibly causing an explosion.
If sparks travel between the inductor windings, then it can arc-weld the wires and cause shorts, which will make the inductor useless.
A simulation without any load connected will give you an idea what levels the output could reach.
resistive load in the sense,a Bulb? and probably a capacitor ?
A bulb will let you confirm proper operation. Even an led with safety resistor may be sufficient to prevent too high a voltage from developing.
And by adding a capacitor, you reduce the high voltage spikes.
How to choose the values? It will require experimentation. It depends on whether you want to leave the resistive load connected at the same time the battery is charging.
Or you might want to disconnect them so the battery can get maximum current. However the changeover should always ensure that some load is present, for reasons stated above.
It will help to run simulations on a variety of configurations.