your question does not make alot of sense.
You cannot boost both the voltage and current.
For example
If your 6V supply is capable of delivering 25AMPS - that is 150 Watts
Power = Volts X Current
if you boost the said voltage to 12V, assuming 100% efficiency! the current available will only be 12.5AMPS.
In practice it is possible to get a voltage converter of ~95% efficient at a specified load,$$$, though more common efficiency would be 50-60% for less $
search "DCDC converters" for more information
Perhaps you should explain what your trying to do?
i am try to use dc motor to charge the car battery 12V.
when the motor rotates, its supply 6V & 1AMPS..
so is it possible to step-up the voltage and current?
Hi Johny,
As Xaccto wrote, you can boost voltage or current tto, but not at same time becouse you can not produce through boosting more energie!
Typical DC/DC converter has an efficiency of ~70-80%, means if you double the voltage _your corrent cant more as 50%multiplyed with 0.75 (efficiency) the 1A (at6V),also your 12 V current wiil be maximum 0.35-0.4A!!
K.
Your welcome.
Energie/power input = voltage in(U) x current in(I) , after converting;
Energie/power output= voltage out(U) x current out(I) but Input power is not more & not equal with output power!
You have to calculate with conversion efficiency(η) too, where (η) is garanted less as 1! Means, after some conversion, you will have still less energie/power product ...
K.
Jea, step up the current means: you can have only a "(voltage)step-down"-converter Sad... Its life.
K.
owh!
tQ
erm,, does its same like voltage converter?
lets say i has battery 12V 12A, if i step-up current double, does its step-down voltage double? so its result be 6V 24A?
So is it; tels us the equation from "10 Mar 2010 17:27" too...Dont forget to calculate with conversion efficiency(η), what is never=1 (100%), as said typically at 0.7--0.9 (70-90%), but can be lower too :-(...
K.