DC-link capacitor ripple current

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Rik797

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Hi guys!

As last part of my switching mode power supply, I need to design the DC bus (or DC link). The equivalent load is 12 ohms (4200 W @ 230 Vac).
By connecting the rectified mains (230 Vac, 50 Hz) to a 4700-uF electrolytic capacitor, I obtain ripple current peaks of 200 A during the capacitor charge (100-Hz frequency).
Ripple current ratings of electrolytic capacitors, however, are usually lower by one order of magnitude (e.g. 20 A)!

What would you suggest me? I am doing something wrong?

Thank you in advance!

Rik
 

you should add a PFC circuit to avoid such ripple since you are dealing with 4200W
 
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    Rik797

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What about a series choke (e.g. 0.5 mH) between the rectified mains and the capacitor?
Is it feasible?
 

What about a series choke (e.g. 0.5 mH) between the rectified mains and the capacitor?
Is it feasible?
Click to expand...
It's the usual "passive PFC" method applied in VFD inverters. But it can hardly raise the power factor above 2/3 or so. Capacitor ripple current has to be determined as RMS value, it won't be larger than about 40 A even without a series inductor.
 
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Thank you FvM, you are correct! Although my inverter is not VFD.
If the ripple current has to be evaluated as an RMS value, than it turns out to be roughly 55 A without the inductor, 32 A with the choke.
Do you think it is a good choice, then?

Thanks!
 

If the ripple current has to be evaluated as an RMS value, than it turns out to be roughly 55 A without the inductor, 32 A with the choke.
Click to expand...
Sounds like more than 4.2 kW load. In any case, you'll need some kind o low ESR capacitors to handle the ripple current.

The alternative is an active PFC with sine input current, but the design is more involved.
 
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    Rik797

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Breaking the filter into multiple smaller parallel caps
ought to up your ability to get rid of the heat (goes
with surface area of the cans, while value tends to
go as volume).

The other, perhaps more severe, ripple current is on
the discharge side, a DC-DC converter imposes square
wave ripple equal to IOUT during the "on" time and
zero during "off" time. An input choke might smooth the
input peak current some but would be unacceptable
between the filter and the converter input rail.
 
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    Rik797

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The other, perhaps more severe, ripple current is on the discharge side
Click to expand...
In many cases, there will be low inductance foil/film capacitors that carry most of the high frequent ripple current.
 
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FvM said:
100 mH/20A is just unrealistic.
Click to expand...

Yes, it is true that a smaller Henry value is needed, if the load is to get above 4 kW.

For comparison, here is my previous layout with a 7 mH choke. After some experimenting I found that is the Henry value that provides an output voltage of 230 V.



On startup, 153 A surge current goes through the capacitor. (That is, if the mains can provide it.)
 
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Thank you all very much!

On startup, 153 A surge current goes through the capacitor. (That is, if the mains can provide it.)
Click to expand...
This should not be an issue since I will arrange a soft start circuit.

100 mH choke provides an output voltage that is, unfortunately, too low for my purposes.

An input choke might smooth the
input peak current some but would be unacceptable
between the filter and the converter input rail.
Click to expand...
What about putting it between the bridge and the capacitor? May it resonate with the inverter, causing some destructive consequences?



In this simulation I used a 3-phase input with a half-bridge rectifier in order to get a 325 Vdc output.

Doubling the capacitance 4.7 mF + 4.7 mF also leads to interesting results, as the current is now split over two caps.



In fact, I arranged a couple of film capacitors on the inverter board, and the troubling current occurs during the charging phase of the electrolytic capacitor.

@BradtheRad: BTW, what is your simulating software?
 

You didn't yet mention three-phase supply. Half-wave rectifier isn't an option for a mains connected power supply, because DC current consumption from mains is strictly banned. This means, if considering three-phase input, then you have to choose three phase bridge and get 540 instead of 310 V bus voltage.
 
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Rik797 said:
In fact, I arranged a couple of film capacitors on the inverter board, and the troubling current occurs during the charging phase of the electrolytic capacitor.
Click to expand...

With the system carrying 4 kW, you have dozens of amperes going back and forth through the capacitors. Besides the steel or copper leads, it means the contact point between the lead and the internal film.

A bank of capacitors will reduce the load on any one component. Notice that you must use a sufficient number, such that the failure of any one will not cause too much burden on the remainder.

@BradtheRad: BTW, what is your simulating software?
Click to expand...

Falstad's interactive animated simulator at falstad.com/circuit.

Click the link below and it will open the falstad website, load my schematic, and run it on your computer.

https://tinyurl.com/mwzpecd

You can adjust values at will. Right-click on a component, and select Edit.
 
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Thank you BradtheRad for your reply.

FvM, I did not considered the issue you mention:
DC current consumption from mains is strictly banned
Click to expand...
but it is true. I think I will simply revert back to my single phase design.

Do you think the choke as shown below is a good idea?

 

Do you think the choke as shown below is a good idea?
Click to expand...
Basically yes. The inductor can be also connected in front of the rectifier, the current waveform doesn't change as long as it's discontinuous.
 
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Great, thank you!

The inductor can be also connected in front of the rectifier
Click to expand...
I have seen that most chokes are common-mode inductors, thus the connection that you propose is quite convenient.
 

But a common mode inductor does not improve the input current power factor, or more exactly, only the small differential inductance part of a common mode choke does.
 
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I thought these ones
**broken link removed**
acted as two series inductors, by connecting them this way:



So you suggest a plain inductor, as in the diagram above the core easily saturates?
 
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