stark43
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How long does it take to go from Detroit to St. Louis?Hello, I have a question. Let's say we are trying to increase the voltage with a flyback converter, how long does it take to reach the desired voltage, is there a formula for this? For example, I want to see 600 volts at the output. How soon can I reach 600 volts
You seem to be answering some other question.[ apologies for the above comment from Barry - your question does indeed have an answer - but it appears Barry needs definite figures to compute same ]
how much energy can you get from your power source ?
Energy stored in a cap = 0.5 C . V^2, and power = energy over time ( J / sec )
so for minimum time to charge, power must be maximum.
Or to re-arrange the above: time = energy / power available = 0.5C.V^2 / power avail
so for 1000uF, 600V, and 20 secs, power in the flyback must be ( average ) = 0.5 1000u. 600^2 / 20
= 180 watts.
90 watts = 40 secs and so on ...
I think this might be what I'm looking for, thank you.[ apologies for the above comment from Barry - your question does indeed have an answer - but it appears Barry needs definite figures to compute same ]
how much energy can you get from your power source ?
Energy stored in a cap = 0.5 C . V^2, and power = energy over time ( J / sec )
so for minimum time to charge, power must be maximum.
Or to re-arrange the above: time = energy / power available = 0.5C.V^2 / power avail
so for 1000uF, 600V, and 20 secs, power in the flyback must be ( average ) = 0.5 1000u. 600^2 / 20
= 180 watts.
90 watts = 40 secs and so on ...
Good to see you here too, sir. I can give an example for clarity. I looked through the datasheet but couldn't see a calculation or a chart.you mention a "flyback".
Shouldn't the rise time also depend on the frequency?[ apologies for the above comment from Barry - your question does indeed have an answer - but it appears Barry needs definite figures to compute same ]
how much energy can you get from your power source ?
Energy stored in a cap = 0.5 C . V^2, and power = energy over time ( J / sec )
so for minimum time to charge, power must be maximum.
Or to re-arrange the above: time = energy / power available = 0.5C.V^2 / power avail
so for 1000uF, 600V, and 20 secs, power in the flyback must be ( average ) = 0.5 1000u. 600^2 / 20
= 180 watts.
90 watts = 40 secs and so on ...
What I did: I opened the datsheet and did a search for "time".Good to see you here too, sir. I can give an example for clarity. I looked through the datasheet but couldn't see a calculation or a chart.
Flyback IC Datasheet
You should ask him for details..I had heard from a friend
nanoseconds ... or seconds...? It makes a big difference for us to give a good answer.it had to make very fast
You say "adjustable" ... so not just at power up?adjustable changes between 50-90 volts
Basically what Easy peasy writes is true. Charging a capacitor is quite good calculable. If you want to spped up: reduce the capacitance, or increase the current.and wanted to change the voltage quickly, what would it need to change?
Thank you sir, if necessary, I will learn more clearly and ask the group again.You should ask him for details..
nanoseconds ... or seconds...? It makes a big difference for us to give a good answer.
You say "adjustable" ... so not just at power up?
And if "adjustable" .. is "falling" also important? Because this is a completele different problem/soluton.
Basically what Easy peasy writes is true. Charging a capacitor is quite good calculable. If you want to spped up: reduce the capacitance, or increase the current.
But there are a lot of parameters that influence the behaviour.
* You can´t guarantee that a xx Watt power supply for 600V can deliver xx Watts when output voltage is just 50V...90V.
* a power supply may be output current limited
* ... or input current limited
* ...or cycle by cycle inductor current limited
* go in hickup mode at overcurrent
* may have a soft start mode .. that is activated just at power up .. or when the difference between setpoint voltage and output voltage is too big.
* output filters
* loop compensation / slope complensation.
* and for sure the load current
You may optimize a power supply for fast rise time ... or low voltage ripple ... or any other parameter.
Klaus
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