Rajinder1268
Full Member level 3
Hi all,
I am using AP63205 DCDC buck converter to generate 5V from a 12V input.
I measured 12V input and the output is 4.96V at the output under no load.
I have a 5R load ( wire wound resistor 5R 50W).
When I connect this why am I only seeing 450mA drawn from the output (I am measuring this with a meter in series). The output drops to 4.90V under load.
Should I not get I = V/R = 4.9V / 5R = 0.98A.
I have measured the resistance of the 5R and this is 5.2R. So with even this slight discrepancy I should be getting close to 900mA not half that value?
I have attached the data sheet. My circuit is as on page 9 of the datasheet (typical application at 5V).
Note I have tried using a different meter to measure the current but it is still the same.
Any suggestions?
Hi all,
Please disregard this post. I have sorted it out. Sorry.
I am using AP63205 DCDC buck converter to generate 5V from a 12V input.
I measured 12V input and the output is 4.96V at the output under no load.
I have a 5R load ( wire wound resistor 5R 50W).
When I connect this why am I only seeing 450mA drawn from the output (I am measuring this with a meter in series). The output drops to 4.90V under load.
Should I not get I = V/R = 4.9V / 5R = 0.98A.
I have measured the resistance of the 5R and this is 5.2R. So with even this slight discrepancy I should be getting close to 900mA not half that value?
I have attached the data sheet. My circuit is as on page 9 of the datasheet (typical application at 5V).
Note I have tried using a different meter to measure the current but it is still the same.
Any suggestions?
--- Updated ---
Hi all,
Please disregard this post. I have sorted it out. Sorry.
Last edited: