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Current to voltage converter

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kam123

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Hi
I want to build a current to voltage converter with op amp, which measure the intensity of sunlight during the day. I'm using a small solar cell taken out from a solar calculator. I've done some research on the web about solar cell and found that its current vary linearly with light intensity. I have LM324 op amp available, since it can be operated with single power supply (eliminating the -V problem)

Can any body suggest a schematic or explain to me how to do it.

thanx
 

47_1203333875.gif
 

Thanx

But what about the value of the resistor and capacitor?

the solar cell I'm using generate about 200 micro ampere during bright sunlight.

Also can u explain to me the use of the capacitor
 

This is so called trasnimpedance amplifier and if you intend to supply it of single voltage you should consider rail-to-rail (input and output) opamp ..
The LM324 may be not suitable for this application but if you have it - give it a try ..

Details on transimpedance amplifiers are here:
http://www.ecircuitcenter.com/Circuits/opitov/opitov.htm

Rgds,
IanP
 

Hello,

R would be intended Vo/Ie, e. g. 5V / 200 uA = 25 kohm, select 24 kohm.
C is necesarry to achieve stability with photodiode capacitance and isn't very critical could choose e.g. 1 up to 100 nF. Higher values can provide a low pass filter.

Regards,
Frank

P.S.: LM324 would be well fitted, cause input range includes negative supply, also output voltage goes near to V- and could be effectively zero with an additionally load resistor. Would be an issue, if you intend to measure down to zero with unusual high dynamic.
 

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